Search This Blog

Friday, 17 April 2015

November 2012


GCSE Physics 5PH2H/01  Scheme – November 2012


1(a)(i)


B

(1)


1(a)(ii)



substitution

(1)


V = 0.5 x 12

evaluation

(1)

V = 6 (V)

  

1(a)(iii)

P / ammeter reading would

increase.

(1)

Q / voltmeter reading

would increase

(1)

They(both) would increase

for two s (2)



  

1(b) component

symbol

graph

All three lines correct for 2 s

One or two lines correct for 1


More than one line against any

box cannot score more than 1

 in total.

(2)



  

1(a)(i)

B

(1)



  

1(a)(ii) substitution

(1)

V = 0.5 x 12

evaluation

(1)

V = 6 (V)

Correct  with no working

shown gains two s.

(2)



  

1(a)(iv) (current/it) would decrease

(1)

smaller/lower/reduce/less

Ignore slowing down (1)



  

2(a) (i) B (1)



  

2(a) (ii) Any one of the following

Rocks

Food

Radon gas

Cosmic rays

Own bodies

Fall-out

Sun/stars

(1)

Plausible named food such as

coffee, brazil nut, bananas

Space

Specified medical/industrial use

of x-rays

Ignore smoke alarms, power

stations (in normal use)

(1)



  

2(a) (iii) An explanation linking

personal circumstances such

as

geographical location

nature of their work

lifestyle

(1)

the consequences such as

radiation from radon

gas/particular rocks/fallout

(eg Chernobyl)

greater exposure to x-rays

greater exposure to cosmic

rays

(1)

(2)



  

2(a) (iv) D (1)



  

2(b) (i) From the graph

Time taken to fall (from 120 to)

60

(1)

= 8 days

(1)

Any other suitable pair of

readings from graph

8.1, 8.2

Full s for correct

even if no working is evident

(2)



  

2(b) (ii) 2.2 (days)

(1)

between 2.0 and 2.5

2

(1)



  

2(b) (iii) Any one of the following:

Mutation of dna

Ionisation of cells

(Increases risk of) cancer

(1)

damage / mutate cells

(1)



  

3(a)(i) B (1)



  

3(a) (ii) (equivalent to a) helium nucleus Two protons and two neutrons

for 2 s

helium/mass of 4 for 1

charge of +2 for 1

correct statement of any

property for 1

(2)



  

3 (b) A description to include any four

of the following

neutron

is captured by a U-235

nucleus

nucleus (is) unstable

nucleus splits

into 2 daughter nuclei (of

similar size)

(2 or more) neutrons are

released

energy is released

collides with /absorbed by

(U-235) nucleus

metastable

named isotopes

(4)



  

3 (c) An explanation linking

moderator slows down

(absorbs energy from)

neutrons

more likely to be captured

/cause fission (if it collides

with a U-235 nuclei)

Reverse argument

(2)



  

4 (a) C

(1)



  

4 a(ii) In the cloud : reason 3

(1)

At the tower: reason 2

(1)

(2)



  

4 a(iii) An explanation linking

the charge was neutralised

(1)

by a transfer/flow of

electrons

(1)

Discharged/ becomes zero

gained electrons / negative

charge

(2)



  

4 (b) substitution

(1)

52 = 2600 x time

transposition

time = 52 / 2600

(1)

evaluation

0.02 (s)

(1)

T = Q / I

Full s for correct

even if no working is evident

(3)



  

4 (c) An explanation linking two of the

following

charges flow through the

metal wire

to the ground / earth

preventing build-up of

(excess) charge

(2)

mention of earthing

discharged / neutral

all objects at the same potential

(2)



  

5(a)(i) substitution

(1)

work done = 84 x 0.25

evaluation

(1)

21(J)

Full s for correct

even if no working is evident (2)



  

5(a)(ii) 21 J Ecf from (a)(i) (1)



  

5(a)(iii) substitution

(1)

KE = ½ x 27 x (2.3)2

evaluation

(1)

= 71.4

(which is approx 71)

V=2.29 gains two s

Reverse argument which shows

that

V = √5.3 gains two s

(2)



  

5 (a)(iv) B

(1)



Indicative Content

QWC *5(b) An explanation linking some of the following points

kinetic energy varies during swing

kinetic energy maximum at bottom of swing

kinetic energy minimum at top of swing

gravitational potential energy(gpe) varies during swing

gpe maximum at top of swing

gpe minimum at bottom of swing

(continuous) interchange of KE and gpe

total amount of energy is constant during one swing

over a  of swings max KE and max PE decreases

energy is dissipated/’lost’ to surroundings

because of air resistance / friction

amplitude/size of swings decrease ( as energy ‘lost’ to

surroundings)

ignore references to momentum

(6)



  

6 (a) (i) C (1)



  

6 (a) (ii) acceleration Recognisable mis-spellings

More than one word written

scores zero EXCEPT for the

phrase

Acceleration due to gravity

which scores 1

(1)



  

6 (b) Substitution

weight = 0.00008 x 10

(1)

evaluation

0.0008 (N)

(1)

8 x 10-4

1/1250

(2)



  

6 (c) Substitution

speed = 13 / 1.7

(1)

evaluation

7.6 (m/s)

(1)

An  which rounds to 7.6

eg 7.647

7.65

7.7

(2)



Indicative Content

QWC *6(d) A explanation including some of the following points

drops near the top are accelerating

due to force of gravity

travel a greater distance in given time

there is air resistance on the drops as they fall

this increases with velocity

resultant force is downward

this reduces resultant force

eventually resultant force is zero

drops have reached terminal/ maximum velocity

drops near bottom are all travelling at terminal velocity

so travel same distance in given time

(6)

No comments:

Post a Comment

Note: only a member of this blog may post a comment.